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Texas Instruments 83 Plus

Loan Amortization
The loan amortization function is used to find the remaining balance, principle, and
interest paid, of a loan with equal end of the month payments. A 36 month loan with
an initial balance of $20,000 and an effective monthly interest rate of 2.00% will be
used.
Step 1 will be to find the amount of the 36 equal monthly payments.
Compounding should remain at P/Y = 1, C/Y = 1.
PMT should be at END
Enter Present Value: PV = -20,000
Enter Future Value: FV = 0
Enter number of periods: N = 36
Enter interest rate: i (I/Y)
= 2
Calculate unknown: ALPHA, SOLVE, PMT,
answer is $784.657
Step 2 will be to find the amount of the 12th payment allocated to interest and the amount
allocated to principle.
2nd QUIT (next to the 2nd key)
APPS, FINANCE
scroll down to 9: bal( and press ENTER.
enter 12 in bal(. Note: it should look like bal(12,
now press ENTER
The screen should now read bal (12 = -14,840.95, which
is the remaining balance of the loan
Press APPS, FINANCE, scroll down to 0: Prn (, ENTER
enter 12,12 (the comma can be found on the fifth row second column) Note:
it should look like Prn (12, 12
the screen should now read Prn = 478.27, this is the amount of the payment assigned
to principle.
Press 2nd, FINANCE, scroll down to A: Int (, ENTER
enter 12,12 Note: it should look like Int (12,12
the screen should now read Int = 306.38, this is the amount of the payment assigned to
pay off interest.

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Last Updated on 1 May 2002, e-mail any comments to: robert.balik@wmich.edu |